Short Answer 
To calculate the maximum kinetic energy of emitted photoelectrons, first identify key variables such as the wavelength (663 nm), work function (1.50 eV), and necessary constants. Calculate photon energy using E = hc/λ, yielding approximately 3 x 10^-19 J, then subtract the work function to find the maximum kinetic energy, which is 0.6 x 10^-19 J.
Step 1: Understand Key Variables
First, gather the essential information required for the calculations. You need to identify:
- Wavelength of the photon (λ): 663 nm, which converts to 663 x 10-9 m.
- Work function (Φ): 1.50 eV, which equates to 2.40 x 10-19 J after conversion.
- Planck’s constant (h): 6.626 x 10-34 J s and the speed of light (c): 3 x 108 m/s.
Step 2: Calculate Photon Energy
Next, you need to calculate the energy of the incident photon using the formula E = hc/λ. Substitute the known values:
- h: 6.626 x 10-34 J s
- c: 3 x 108 m/s
- λ: 663 x 10-9 m
This yields the energy of the photon, which should calculate to approximately 3 x 10-19 J.
Step 3: Determine Maximum Kinetic Energy
Finally, use the photon energy to find the maximum kinetic energy (K.E.) of the emitted photoelectrons using:
- K.E. = E РŒ¶
Substituting the values results in:
- K.E. = (3 x 10-19 J) – (2.40 x 10-19 J) = 0.6 x 10-19 J.
This indicates that the maximum kinetic energy of the emitted photoelectrons is 0.6 x 10-19 J.